MATH SOLVE

2 months ago

Q:
# A person owns two shops. This year the telephone bill for the first shop was $560 less than three timesthree times the telephone bill for the second shop. The total telephone expense for both shops was $2752. What was the cost of each shop's telephone service for the year?

Accepted Solution

A:

Answer:The telephone bill for the first shop is $1924 and for the second shop is $828Step-by-step explanation:Let's call A the cost of the telephone service of the first shop, and B the cost of the telephone service of the second shop.From the sentence, the telephone bill for the first shop was $560 less than three times the telephone bill for the second shop, we can formulate the equation 1, as:A = 3*B - 560Additionally from the sentence, the total telephone expense for both shops was $2752, we can formulate the equation 2 as:A + B = 2752For found the values of A and B, we need to take A from equation 1 and replace its value on equation 2, and solve for B. This is:A + B = 2752(3*B - 560) + B = 27523*B - 560 + B = 27524*B = 2752 + 5604*B = 3312B = 3312/4 B = 828Replacing the value of B on equation 1, we get:A = 3*828 - 560A = 2484 - 560A = 1924So, the value of A is 1924 and the value of B is 828, That means that the telephone bill for the first shop is $1924 and the telephone bill for the second shop is $828